remq(obj, xs)
remv(obj, xs)
remove(obj, xs)
Return a list containing the elements of xs with all occurrences of obj removed.
The equivalence test for remq is is_eq, for remv is
is_eqv, and for remove is is_equal.
remq(1, [1, 2, 1, 3])
// [2, 3]
remv(1020032003209020020020, [1020032003209020020020, 2, 1020032003209020020020, 3])
// [2, 3]
remove([1,2,3], [[1,2,3], [4,5,6], [1,2,3]])
// [[4, 5, 6]]